2025-05-30
Solutions to Principles of Quantum Mechanics
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目录

Chapter 10 Systems with $N$ Degrees of Freedom
10.1 $N$ Particles in One Dimension
10.2 More Particles in More Dimensions
10.3 Identical Particles

Chapter 10 Systems with NN Degrees of Freedom

10.1 NN Particles in One Dimension

Exercise 10.1.1 Show the following:

(1)

[Ω1(1)I(2),I(1)Λ2(2)]=0 for any Ω1(1) and Λ2(2)(10.1.17a)[\Omega_{1}^{(1)}\otimes I^{(2)}, I^{(1)}\otimes \Lambda_{2}^{(2)}]=0~\text{for any}~\Omega_{1}^{(1)}~\text{and}~\Lambda_{2}^{(2)}\tag{10.1.17a}

(2)

(Ω1(1)Γ2(2))(θ1(1)Λ2(2))=(Ωθ)1(1)(ΓΛ)2(2)(10.1.17b)(\Omega_{1}^{(1)}\otimes\Gamma_{2}^{(2)})(\theta_{1}^{(1)}\otimes\Lambda_{2}^{(2)})=(\Omega\theta)_{1}^{(1)}\otimes(\Gamma\Lambda)_{2}^{(2)}\tag{10.1.17b}

(3)If

[Ω1(1),Λ1(1)]=Γ1(1)[\Omega_{1}^{(1)},\Lambda_{1}^{(1)}]=\Gamma_{1}^{(1)}

then

[Ω1(1)(2),Λ1(1)(2)]=Γ1(1)I(2)(10.1.17c)[\Omega_{1}^{(1)\otimes(2)},\Lambda_{1}^{(1)\otimes(2)}]=\Gamma_{1}^{(1)}\otimes I^{(2)}\tag{10.1.17c}

and similarly with 121\to 2.

(4)

(Ω1(1)(2)+Ω2(1)(2))2=(Ω12)(1)I(2)+I(1)(Ω22)(2)+2Ω1(1)Ω2(2)(10.1.17d)(\Omega_{1}^{(1)\otimes (2)}+\Omega_{2}^{(1)\otimes(2)})^{2}=(\Omega_{1}^{2})^{(1)}\otimes I^{(2)}+I^{(1)}\otimes (\Omega_{2}^{2})^{(2)}+2\Omega_{1}^{(1)}\otimes\Omega_{2}^{(2)}\tag{10.1.17d}

Exercise 10.1.2 Imagine a fictitious world in which the single-particle Hilbert space is two-dimensional. Let us denote the basis vectors by +|+\rangle and |-\rangle. Let image

be operators in V1\mathbb{V}_1 and V2\mathbb{V}_2, respectively (the ±\pm signs label the basis vectors. Thus b=+σ1(1)b=\langle+| \sigma_1^{(1)}|-\rangle etc.) The space V1V2\mathbb{V}_1 \otimes \mathbb{V}_2 is spanned by four vectors ++|+\rangle \otimes|+\rangle, +|+\rangle \otimes|-\rangle, +|-\rangle\otimes|+\rangle, |-\rangle\otimes|-\rangle. Show (using the method of images or otherwise) that

(1) image

(Recall that αβ\langle\alpha|\otimes\langle\beta| is the bra corresponding to αβ|\alpha\rangle\otimes|\beta\rangle.)

(2) σ2(1)(2)=(ef00gh0000ef00gh)\sigma_{2}^{(1)\otimes(2)}=\begin{pmatrix} e & f & 0 & 0\\ g & h & 0 & 0\\ 0 & 0 & e & f\\ 0 & 0 & g & h \end{pmatrix}

(3) (σ1σ2)(1)(2)=σ1(1)σ2(2)=(aeafbebfagahbgbhcecfdedfcgchdgdh)(\sigma_{1}\sigma_{2})^{(1)\otimes(2)}=\sigma_{1}^{(1)}\otimes\sigma_{2}^{(2)}=\begin{pmatrix} ae & af & be & bf\\ ag & ah & bg & bh\\ ce & cf & de & df\\ cg & ch & dg & dh \end{pmatrix}

Do part (3) in two ways, by taking the matrix product of σ1(1)(2)\sigma_{1}^{(1)\otimes (2)} and σ2(1)(2)\sigma_{2}^{(1)\otimes (2)} and by directly computing the matrix elements of σ1(1)σ2(2)\sigma_{1}^{(1)}\otimes\sigma_{2}^{(2)}.

Exercise 10.1.3 Consider the Hamiltonian of the coupled mass system:

H=p122m+p222m+12mω2[x12+x22+(x1x2)2]\mathscr{H}=\dfrac{p_{1}^{2}}{2m}+\dfrac{p_{2}^{2}}{2m}+\dfrac{1}{2}m\omega^{2}[x_{1}^{2}+x_{2}^{2}+(x_{1}-x_{2})^{2}]

We know from Example 1.8.6 that H\mathscr{H} can be decoupled if we use normal coordinates

xI,II=x1±x221/2x_{\text{I},\text{II}}=\dfrac{x_{1}\pm x_{2}}{2^{1/2}}

and the corresponding momenta

pI,II=p1±p221/2p_{\text{I},\text{II}}=\dfrac{p_{1}\pm p_{2}}{2^{1/2}}

(1) Rewrite H\mathscr{H} in terms of normal coordinates. Verify that the normal coordinates are also canonical, i.e., that

{xi,pj}=δij etc.;i,j=I,II\{x_{i},p_{j}\}=\delta_{ij}~\text{etc.;}\qquad i,j=\text{I},\text{II}

Now quantize the system, promoting these variables to operators obeying

[Xi,Pj]=iδij etc.;i,j=I,II[X_{i},P_{j}]=\mathrm{i}\hbar\delta_{ij}~\text{etc.;}\qquad i,j=\text{I},\text{II}

Write the eigenvalue equation for HH in the simultaneous eigenbasis of XIX_{\text{I}} and XIIX_{\text{II}}.

(2) Quantize the system directly, by promoting x1x_{1}, x2x_{2}, p1p_{1}, and p2p_{2} to quantum operators. Write the eigenvalue equation for HH in the simultaneous eigenbasis of X1X_{1} and X2X_{2}. Now change from x1x_{1}, x2x_{2} (and of course /x1\partial/\partial x_{1}, /x2\partial/\partial x_{2}) to xIx_{\text{I}}, xIIx_{\text{II}} (and /xI\partial/\partial x_{\text{I}}, /xII\partial/\partial x_{\text{II}}) in the differential equation. You should end up with the result form part (1).

10.2 More Particles in More Dimensions

Exercise 10.2.1 (Particle in a Three-Dimensional Box) Recall that a particle in a one-dimensional box extending from x=0x=0 to LL is confined to the region 0xL0 \leqslant x \leqslant L; its wave function vanishes at the edges x=0x=0 and LL and beyond (Exercise 5.2.5). Consider now a particle confined in a three-dimensional cubic box of volume L3L^3. Choosing as the origin one of its corners, and the x,yx, y, and zz axes along the three edges meeting there, show that the normalized energy eigenfunctions are

ψE(x,y,z)=(2L)1/2sin(nxπxL)(2L)1/2sin(nyπyL)(2L)1/2sin(nzπzL)\psi_E(x, y, z)=\left(\frac{2}{L}\right)^{1 / 2} \sin \left(\frac{n_x \pi x}{L}\right)\left(\frac{2}{L}\right)^{1 / 2} \sin \left(\frac{n_y \pi y}{L}\right)\left(\frac{2}{L}\right)^{1 / 2} \sin \left(\frac{n_z \pi z}{L}\right)

where

E=2π22ML2(nx2+ny2+nz2)E=\frac{\hbar^2 \pi^2}{2 M L^2}\left(n_x^2+n_y^2+n_z^2\right)

and nin_i are positive integers.

Exercise 10.2.2 Quantize the two-dimensional oscillator for which

H=px2+py22m+12mωx2x2+12mωy2y2\mathscr{H}=\frac{p_x^2+p_y^2}{2 m}+\frac{1}{2} m \omega_x^2 x^2+\frac{1}{2} m \omega_y^2 y^2

(1) Show that the allowed energies are

E=(nx+1/2)ωx+(ny+1/2)ωy,nx,ny=0,1,2,E=\left(n_x+1 / 2\right) \hbar \omega_x+\left(n_y+1 / 2\right) \hbar \omega_y, \quad n_x, n_y=0,1,2, \ldots

(2) Write down the corresponding wave functions in terms of single oscillator wave functions. Verify that they have definite parity (even/odd) number xx,yyx \rightarrow-x, y \rightarrow-y and that the parity depends only on n=nx+nyn=n_x+n_y.

(3) Consider next the isotropic oscillator (ωx=ωy)\left(\omega_x=\omega_y\right). Write explicit, normalized eigenfunctions of the first three states (that is, for the cases n=0n=0 and 1). Reexpress your results in terms of polar coordinates ρ\rho and ϕ\phi (for later use). Show that the degeneracy of a level with E=(n+1)ωE=(n+1) \hbar \omega is (n+1)(n+1).

Exercise 10.2.3 Quantize the three-dimensional isotropic oscillator for which

H=px2+py2+pz22m+12mω2(x2+y2+z2)\mathscr{H}=\frac{p_x^2+p_y^2+p_z^2}{2 m}+\frac{1}{2} m \omega^2\left(x^2+y^2+z^2\right)

(1) Show that E=(n+3/2)ωE=(n+3 / 2) \hbar \omega; n=nx+ny+nzn=n_x+n_y+n_z; nx,ny,nz=0,1,2,n_x, n_y, n_z=0,1,2, \ldots.

(2) Write the corresponding eigenfunctions in terms of single-oscillator wave functions and verify that the parity of the level with a given nn is (1)n(-1)^n. Reexpress the first four states in terms of spherical coordinates. Show that the degeneracy of a level with energy E=E= (n+3/2)ω(n+3 / 2) \hbar \omega is (n+1)(n+2)/2(n+1)(n+2) / 2.

10.3 Identical Particles

Exercise 10.3.1 Two identical bosons are found to be in states ϕ|\phi\rangle and ψ|\psi\rangle. Write down the normalized state vector describing the system when ϕψ0\langle\phi \mid \psi\rangle \neq 0.

Exercise 10.3.2 When an energy measurement is made on a system of three bosons in a box, the nn values obtained were 33, 33, and 44. Write down a symmetrized, normalized state vector.

Exercise 10.3.3 Imagine a situation in which there are three particles and only three states aa, bb, and cc available to them. Show that the total number of allowed, distinct configurations for this system is

(1) 27 if they are labeled

(2) 10 if they are bosons

(3) 1 if they are fermions

Exercise 10.3.4 Two identical particles of mass mm are in a one-dimensional box of length LL. Energy measurement of the system yields the value Esys=2π2/mL2E_{\text{sys}}=\hbar^2 \pi^2/mL^2. Write down the state vector of the system. Repeat for Esys=52π2/2mL2E_{\text{sys}}=5 \hbar^2 \pi^2 / 2 m L^2. (There are two possible vectors in this case.) You are not told if they are bosons or fermions. You may assume that the only degrees of freedom are orbital.

Exercise 10.3.5 Consider the exchange operator P12P_{12} whose action on the XX basis is

P12x1,x2=x2,x1P_{12}\left|x_1, x_2\right\rangle=\left|x_2, x_1\right\rangle

(1) Show that P12P_{12} has eigenvalues ±1\pm 1. (It is Hermitian and unitary.)

(2) Show that its action on the basis ket ω1,ω2\left|\omega_1, \omega_2\right\rangle is also to exchange the labels 11 and 22, and hence that VS/A\mathbb{V}_{S/A} are its eigenspaces with eigenvalues ±1\pm 1.

(3) Show that P12X1P12=X2P_{12} X_1 P_{12}=X_2, P12X2P12=X1P_{12} X_2 P_{12}=X_1 and similarly for P1P_1 and P2P_2. Then show that P12Ω(X1,P1;X2,P2)P12=Ω(X2,P2;X1,P1)P_{12} \Omega\left(X_1, P_1 ; X_2, P_2\right) P_{12}=\Omega\left(X_2, P_2 ; X_1, P_1\right). [Consider the action on x1,x2\left|x_1, x_2\right\rangle or p1,p2\left|p_1, p_2\right\rangle. As for the functions of XX and PP, assume they are given by power series and consider any term in the series. If you need help, peek into the discussion leading to Eq. (11.2.22).]

(4) Show that the Hamiltonian and propagator for two identical particles are left unaffected under HP12HP12H \rightarrow P_{12} H P_{12} and UP12UP12U \rightarrow P_{12} U P_{12}. Given this, show that any eigenstate of P12P_{12} continues to remain an eigenstate with the same eigenvalue as time passes, i.e., elements of VS/A\mathbb{V}_{S/A} never leave the symmetric or antisymmetric subspaces they start in.

Exercise 10.3.6 Consider a composite object such as the hydrogen atom. Will it behave as a boson or fermion? Argue in general that objects containing an even/odd number of fermions will behave as bosons/fermions.