Chapter 15 Addition of Angular Momenta
15.1 A Simple Example
Exercise 15.1.1 Derive Eqs. (15.1.10) and (15.1.11). It might help to use
S1⋅S2=S1zS2z+21(S1+S2−+S1−S2+)(15.1.12)
Exercise 15.1.2 In addition to the Coulomb interaction, there exists another, called the hyperfine interaction, between the electron and proton in the hydrogen atom. The Hamiltonian describing this interaction, which is due to the magnetic moments of the two particles is,
Hhf=AS1⋅S2(A>0)(15.1.22)
(This formula assumes the orbital state of the electron is ∣1,0,0⟩.) The total Hamiltonian is thus the Coulomb Hamiltonian plus Hhf.
\noindent (1) Show that Hhf splits the ground state into two levels:
E+E−=−Ry+4ℏ2A=−Ry−43ℏ2A(15.1.23)
and that corresponding states are triplets and singlet, respectively.
(2) Try to estimate the frequency of the emitted radiation as the atom jumps from the triplet to the singlet. To do so, you may assume that the electron and proton are two dipoles μe and μp separated by a distance a0, with an interaction energy of the order (The description here is oversimplified; both Hhf and Hhf are rather tricky to derive. Our aim is just to estimate ∣A∣ and not to get into its precise origin.)
Hhf≅a03μe⋅μp
Show that this implies that the constant in Eq. (15.1.22) is
A∼2mc2e2Mc(5.6)ea031
(where 5.6 is the g factor for the proton), and that
ΔE=E+−E−=Aℏ2
is a correction of order (m/M)α2 relative to the ground-state energy. Estimate that the frequency of emitted radiation is a few tens of centimeters, using the mnemonics from Chapter 13. The measured value is 21.4 cm. This radiation, called the 21−cm line, is a way to detect hydrogen in other parts of the universe.
(3) Estimate the probability ratio P(triplet)/P(singlet) of hydrogen atoms in thermal equilibrium at room temperature.
15.2 The General Problem
Exercise 15.2.1 (1) Verify that ∣j1j1,j2j2⟩ is indeed a state of j=j1+j2 by letting J2=J12+J22+2J1zJ2z+J1+J2−+J1−J2+ act on it.
(2) Verify that the right-hand side of Eq. (15.2.8) indeed has angular momentum j=j1+j2−1.
Exercise 15.2.2 Find the CG coefficients of
(1) 21⊗1=23⊕21
(2) 1⊗1=2⊕1⊕0
Exercise 15.2.3 Argue that 21⊗21⊗21=23⊕21⊕21.
Exercise 15.2.4 Derive Eqs. (15.2.19) and (15.2.20).
Exercise 15.2.5 (1) Show that P1=43I+(S1⋅S2)/ℏ2 and P0=41I−(S1⋅S2)/ℏ2 are projection operators, i.e., obey PiPj=δijPj [use Eq. (14.3.39)].
(2) Show that these project into the spin-1 and spin-0 spaces in 21⊗21=1⊕0.
Exercise 15.2.6 Construct the project operators P± for the j=l±1/2 subspaces in the addition L+S=J.
Exercise 15.2.7 Show that when we add j1 to j1, the states with j=2j1 are symmetric. Show that the states with j=2j1=1 are antisymmetric. (Argue for the symmetry of the top states and show that lowering does not change symmetry.) This pattern of alternating symmetry continues as j decreases, but is harder to prove.
15.3 Irreducible Tensor Operators
Exercise 15.3.1 (1) Show that Eq. (15.3.11) follows from Eq. (15.3.10) when one considers infinitesimal rotations. (Hint: Dq′q(k)=⟨kq′∣I−(iδθ⋅J)/ℏ∣kq⟩. Pick δθ along, say, the x direction and then generalize the result to the other directions.)
(2) Verify that the spherical tensor V1q constructed out of V as in Eq. (15.3.15) obeys Eq. (15.3.11).
Exercise 15.3.2 It is claimed that q∑(−1)qSkqTk(−q) is a scalar operator.
(1) For k=1, verify that this is just S⋅T.
(2) Prove it in general by considering its response to a rotation. [Hint: D−m,−m′(j)=(−1)m−m′(Dm,m′(j))∗.]
Exercise 15.3.3 (1) Using ⟨jj∣jj,10⟩=[j/(j+1)]1/2 show that
⟨αj∣∣J1∣∣α′j′⟩=δαα′δjjℏ[j(j+1)]1/2
(2) Using J⋅A=JzAz+21(J−A++J+A−)(where A±=Ax±iAy ) argue that
⟨α′jm′∣J⋅A∣αjm⟩=c⟨α′j∣∣A∣∣αj⟩
where c is a constant independent of α,α′ and A. Show that c=ℏ[j(j+1)]1/2δm,m′.
(3) Using the above, show that
⟨α′jm′∣Aq∣αjm⟩=ℏ2j(j+1)⟨α′jm∣J⋅A∣αjm⟩⟨jm′∣Jq∣jm⟩
Exercise 15.3.4 (1) Consider a system whose angular momentum consists of two parts J1 and J2 and whose magnetic moment is
μ=γ1J1+γ2J2
In a state ∣jm,j1j2⟩ show, using Eq. (15.3.19), that
⟨μx⟩=⟨μy⟩=0⟨μz⟩=mℏ[2γ1+γ2+2(γ1−γ2)j(j+1)j1(j1+1)−j2(j2+1)]
(2) Apply this to the problem of a proton (g=5.6) in a 2P1/2 state and show that ⟨μz⟩= ±0.26 nuclear magnetons.
(3) For an electron in a 2P1/2 state show that ⟨μz⟩=±31 Bohr magnetons.
Exercise 15.3.5 Show that ⟨jm∣Tkq∣jm⟩=0 if k>2j.
15.4 Explanation of Some “Accidental” Degeneracies